find distance only section 6 Practice Questions Answers Test with Solutions & More Shortcuts
direction & distance sense test PRACTICE TEST [15 - EXERCISES]
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
Question : 16 [SSC CGL Tier-I 2014]
Rahul travelled from a point and straightly goes to point ‘Y’ at a distance of 90 metres. He turned right and walked 40 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 40 metres. How far he is from the starting point ?
a) 10 metres
b) 30 metres
c) 70 metres
d) 20 metres
Answer »Answer: (d)
Required distance = AE
= 20 metre
Question : 17
Jai Prakash started walking towards south from the point A, walked 20 m and reached a point B, Again, he turned left and walked 20 m and reached a point C. Now he turned 45° anticlockwise, walked a distance of 20 √2 m and reached a point D. What approximately is the shortest distance between the point A and D?
a) 30 m
b) 40$√{2}$ m
c) Can't say
d) 40 m
Answer »Answer: (d)
Here, AC = $√{20^2 + 20^2} = 20$√{2}$ m
Since AB = BC
∴ ∠ACB = ∠BAC = 45°
∴ ∠ACD = 90°
Now,
AD2 = AC2 + CD2
= 800 + 800 = 1600
∴ AD = $√{1600}$ = 40 m
Question : 18
A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point ?
a) 5 km
b) 4 km
c) 3 km
d) 7 km
Answer »Answer: (a)
The movements of the man are as shown in the figure,
(A to B, B to C, C to D, D to E)
Clearly, DF = BC = 5km.
EF = (DE - DF) = (9 - 5)km = 4km.
BF = CD = 2km
AF =AB + BF = AB + CD = (1 + 2)km = 3km.
∴ Man's distance from initial position A
= AE = $√{AF^2 + FE^2}$
= $√{3^2 + 4^2}$
= $√25$ = 5m.
Question : 19
From point A, Swati started walking in south direction. She walked for 4 m and took a right turn. Next she walked 5 m and turned to her left. Next she walked for 3 m and turned to her right. Next she walked 4 m and turned to her right again. Next she walked 15 m and turned to her right again and stopped at point B after walking 7 m. Find distance AB.
a) $3√21 m$
b) $2√19 m$
c) $2√22 m$
d) $4√17 m$
e) None of these
Answer »Answer: (e)
AB = $√(8^2 +2^2 )= 2√17 m$
Question : 20 [SSC Com Matric 2000]
Pran and Khan start from their office and walk in opposite direction, each travelling 10 km. Pran then turns left and walks 10 km. While Khan turns right and walks 10 km. How far they are now from each other?
a) 5 km
b) 20 km
c) 0 km
d) 10 km
Answer »Answer: (b)
It is clear from the diagram that they are at a distance of 20 km.
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